Question Bug in Get_number

int isname(const char *str, const char *namelist) { char *newlist; char *curtok; if (!str || !*str || !namelist || !*namelist) return 0; if (!strcmp(str, namelist)) /* the easy way */ return 1; newlist = strdup(namelist); /* make a copy since strtok 'modifies' strings */ for(curtok = strtok(newlist, WHITESPACE); curtok; curtok = strtok(NULL, WHITESPACE)) if(curtok && is_abbrev(str, curtok)) { /* Don't allow abbreviated numbers. - Sryth */ if (isdigit(*str) && (atoi(str) != atoi(curtok))) - return 0; + continue; free(newlist); return 1; } free(newlist); return 0; } my get_number int get_number(char **name) { int i; char number[MAX_INPUT_LENGTH], *ppos; /* * These lines was added to make possible the dot sign to be used as a magic * char on isname() function. */ if (!isdigit(**name)) return (1); *number = '\0'; if ((ppos = strchr(*name, '.')) != NULL) { *ppos++ = '\0'; strlcpy(number, *name, sizeof(number)); strcpy(*name, ppos); for (i = 0; *(number + i); i++) if (!isdigit(*(number + i))) return (0); return (atoi(number)); } return (1); }